Tizian 「ティツィアーン」
e7f3abdb8d
Korean names a Hanja by its meaning, then its sound; simplified Chinese shares some radicals' forms with Japanese (麦), which showed twice, and writes 黑 as itself. A test can read a language's strokes beforehand. Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com> Signed-off-by: Tizian 「ティツィアーン」 <raisondetredev@pm.me>
57 lines
2.1 KiB
Dart
57 lines
2.1 KiB
Dart
import 'package:flutter_test/flutter_test.dart';
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import 'package:halkyon_learn_flutter/src/feature/kanji/model/radical.dart';
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void main() {
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test('the 214 Kangxi radicals in their order, by their strokes from 1 '
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'to 17', () {
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expect(
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[for (final radical in radicals) radical.number],
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[
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for (var number = 1; number <= 214; number++) number,
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],
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);
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final strokes = [for (final radical in radicals) radical.strokes];
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expect(strokes, orderedEquals([...strokes]..sort()));
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expect((strokes.first, strokes.last), (1, 17));
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// Const, as the table is: a record compares its lists by identity.
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expect(radicals[84], const (
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number: 85,
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character: '水',
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variants: ['氵'],
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strokes: 4,
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name: 'water',
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));
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});
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test('each is one character, as is every form it takes in kanji', () {
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for (final radical in radicals) {
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for (final form in [radical.character, ...radical.variants]) {
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expect(form.runes, hasLength(1), reason: '${radical.number}');
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}
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}
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});
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test("a radical's label is the dictionary's", () {
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expect(radicalLabel(85), 'radical:85');
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});
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test('the forms a radical takes in each language: simplified Chinese its '
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"own, traditional Chinese and Korean without Japanese's own", () {
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final speech = radicals[148];
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final dragon = radicals[211];
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final food = radicals[183];
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expect(radicalFormsIn(speech, 'zh-Hans'), ['讠']);
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expect(radicalFormsIn(speech, 'zh-Hant'), isEmpty);
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expect(radicalFormsIn(dragon, 'ja'), ['竜']);
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expect(radicalFormsIn(dragon, 'zh'), ['龙']);
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expect(radicalFormsIn(dragon, 'ko'), isEmpty);
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// Simplified Chinese writes 食 as 饣 at a character's side, not 飠.
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expect(radicalFormsIn(food, 'zh-CN'), ['饣']);
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expect(radicalFormsIn(food, 'zh-TW'), ['飠']);
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expect(radicalsIn('zh-Hans')[148].variants, ['讠']);
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// Each form once, never the radical itself.
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expect(radicalFormsIn(radicals[198], 'zh'), ['麦']);
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expect(radicalFormsIn(radicals[202], 'zh'), isEmpty);
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expect((hasRadicals('ko'), hasRadicals('el')), (true, false));
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});
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}
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